Flashcards for topic Dispersion and Spectra
Given a thin lens with red and violet focal lengths of 90.0 cm and 86.4 cm respectively, calculate the dispersive power of the lens material and explain what this value indicates.
Step 1: Use the relationship between focal length and refractive index:
Step 2: Calculate the difference in refractive indices:
Step 3: Calculate the average refractive index minus 1:
Step 4: Calculate dispersive power:
Significance: This value (0.042) indicates the lens material's ability to separate different wavelengths. A higher dispersive power means greater chromatic aberration, requiring correction in precision optical instruments.
How does dispersion manifest in optical systems and what specific problems does it cause in imaging applications?
Manifestations of Dispersion:
Problems in Imaging Applications:
Chromatic Aberration:
Color Fringing: Colored edges around high-contrast boundaries
Reduced Resolution: Blurring due to overlapping color focal points
Reduced Contrast: Especially in systems requiring precise focus
Spectral Artifacts: False colors or missing wavelength information
Solutions include achromatic lenses (crown+flint combinations), apochromatic designs (correcting for three wavelengths), and reflective optics (mirrors that avoid dispersion entirely).
Explain the relationship between the angle of minimum deviation () and the refracting angle () of a prism, and derive the formula for the refractive index.
For a light ray passing symmetrically through a prism:
The angle of minimum deviation () occurs when the ray passes symmetrically through the prism
At this position, the angles of incidence and emergence are equal
The mathematical relationship is:
Derivation:
This equation allows precise determination of refractive index by measuring the minimum deviation angle experimentally.
How do you calculate the net angular dispersion and average deviation when light passes through two prisms with different dispersive powers placed in reversed orientation?
Net angular dispersion (δv-δr):
Net average deviation (δy):
Application: Used in the design of achromatic prisms and compound lenses that minimize chromatic aberration while maintaining desired optical properties.
How would you design an optical system that achieves "dispersion without average deviation" and why would this be useful?
To create dispersion without average deviation:
Design approach:
Requirements: • The materials must have different dispersive powers (ω ≠ ω') • The prism angles must be calculated precisely to cancel average deviation • The material with higher dispersive power typically has smaller prism angle
Applications: • Direct vision spectroscopes • Dispersing elements in spectrometers that maintain beam direction • Chromatic correction in optical systems • Prism systems where wavelength separation is needed without beam deflection
This principle is foundational for achromatic and apochromatic lens design.
What is the principle behind using a prism combination with reversed refracting angles to achieve dispersion without average deviation?
The principle involves:
Note: This is the foundational principle behind achromatic optical devices that correct chromatic aberration.
What is the physical basis for the different focal positions of red and violet light after passing through a dispersing element and focusing lens, and how does this relate to the refractive index equation?
The different focal positions result from wavelength-dependent refraction, explained by:
Refractive Index Variation: The refractive index (μ) varies with wavelength according to Cauchy's equation: μ = μ₀ + A/λ² where A is Cauchy's constant and λ is wavelength
Dispersion Mechanism:
Focal Position Effect:
The dispersive power (ω) quantifies this effect: ω = (μᵥ - μᵣ)/(μy - 1), where μᵥ, μᵣ, and μy are the refractive indices for violet, red, and yellow light respectively.
This wavelength-dependent focusing forms the basis for both spectrum analysis and chromatic aberration in optical systems.
How does a spectrometer demonstrate dispersion of white light, and why does the telescope need to be repositioned to view different colors?
When white light passes through a spectrometer:
The telescope must be repositioned because:
This demonstrates Snell's law and the wavelength dependence of refractive index in action.
What makes a spectrum "pure" versus "impure" in spectroscopy, and how does the spectrometer setup ensure purity?
Pure vs. Impure Spectrum:
How a spectrometer ensures spectral purity:
Narrow slit: Restricts the width of the incoming light beam, preventing multiple light paths that would cause spatial overlap
Collimation: The collimator lens converts divergent light from the slit into parallel rays, ensuring all rays of a given wavelength strike the prism at the same angle
Proper focus: The telescope focuses parallel rays of each wavelength to a single point in its focal plane
Precision rotation: The ability to precisely rotate the telescope allows isolation and measurement of specific wavelengths
If the slit were too wide or the collimation imperfect, different points of the slit would produce overlapping spectra, resulting in an impure spectrum with diffused color impressions.
In a spectrometer setup, what are the components and their functions for measuring the angle of minimum deviation?
A spectrometer for minimum deviation measurement consists of:
Collimator (C):
Prism on rotating table:
Telescope (T):
Measurement scales:
The procedure requires coordinated rotation of both the prism and telescope to find the exact position where deviation is minimized, allowing precise determination of optical properties.
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